Limit action

Sam Granger · 10-13-2007, 10:30 PM

Hey guys! I currently have a js function. It is called with a html link and it displays a snippet of html.

How can I limit the ammount of times this function displays the html? I want it to only show it 3 times, and after that i want it to display an error box. How can this be achieved? :)

Salathe · 10-13-2007, 11:32 PM

Although you might not think the same, your post is really very vague and lacking details. Post up your code, or a succinct sample, and it'll be ten times easier to provide exactly what you want.

Sam Granger · 10-13-2007, 11:50 PM

Quote:

Originally Posted by Salathe

Although you might not think the same, your post is really very vague and lacking details. Post up your code, or a succinct sample, and it'll be ten times easier to provide exactly what you want.

Ok, right now I have a button with the following link: javascript:createFileInput();

The js createFileInput function:

PHP Code:


			
//** FUNCTION: Create Upload Form
    function createFileInput(path) {
        var tbody = document.getElementById('list_body').getElementsByTagName('tbody')[0];        
    // Create Table Row    
        var tr = document.createElement("tr")
        if (bg_color) { tr.className="on"; bg_color= false; } else { bg_color = true;}
    // Create Table Cell
        var td = document.createElement("td")
        td.id='upload_'+count;
        td.width='100%';
        var output = new Array();
        output.push("<form id='frmUpload_"+count+"' target='uploadForm' method='post' enctype='multipart/form-data' action='/cgi-bin/upload.cgi?sid="+sid+"'>");
        output.push("<input type='hidden' name='path' value='"+path+"'>");
        output.push("<input style='width:100%;' type='file' name='filename' ><\/form>");
        td.innerHTML = output.join('');
        tr.appendChild(td);
        tbody.appendChild(tr);    
        uploads.push(count);
        if (count != 0 ) {
            var tiggerForm = document.getElementById('frmUpload_'+count);
            tiggerForm['filename'].click();
            tiggerForm = null;
        }
        count++;

        
    }

Sam Granger · 10-15-2007, 04:12 PM

Sorry guys, I must of posted this when I was completely sleepy, pretty simple to do, I have completed it myself. Thanks though Salathe! ;)