preselect from drop list php

KingOfTheSouth · 02-14-2012, 04:19 PM

Hey all I have an issue I need some help on. I have two drop down lists in html that are being populated by php. My first drop down is called "IN" and you select a time time then when finished with task you select "OUT" and select the time. It is just like a time-sheet. But Once I get my first "OUT" selection for the day I want the "IN" to be populated by the last "OUT" that was selected. Does this make any sense?

tony · 02-15-2012, 04:07 AM

That seems more like a javascript would help you on that one. Is that how you are trying to do it or purely in PHP? That could also be done.

KingOfTheSouth · 02-15-2012, 03:57 PM

JavaScript is what I wanted to do at first, but I suck at JavaScript it is so confusing. I was thinking PHP but didn't know if it could be done like that.

AxelG · 02-18-2012, 08:21 PM

There is easy solution in javascript using jQuery. It is more easy and faster to create javascript with jQuery.

KingOfTheSouth · 02-21-2012, 04:03 PM

I am not that good at any JavaScripting I have used JQuery but just stuff from JQuery.com so I don't know it that well.

KingOfTheSouth · 03-13-2012, 06:31 PM

I got this figured out. Where is what I did...

PHP Code:


			
<select name="start">

          <option value="">-Select One-</option>

          <?php

$query = "SELECT " . $tab['timesheet'] . ".stop FROM " . $tab['timesheet'] . " WHERE user = " . $user['id'] . " ORDER BY  timesheets.stop DESC LIMIT 1";



$result   = mysql_fetch_array(mysql_query($query));

$lastTime = date("g:i A", strtotime("01/27/2012 " . $result['stop']));

$start    = date('G', strtotime("01/27/2012"));

$minutes  = 0;



for ($i = 0; $i < 96; $i++) {

                $start = date("g:i A", strtotime("01/27/2012 + " . $minutes . " minutes"));

                

?>

          <option value="<?php

                echo "$start";

?>" <?php

                echo ($start == $lastTime) ? "selected" : "";

?> >

          <?php

                echo $start;

?>

         </option>

          <?php

                $minutes += 15;

                $start = date("G", strtotime("01/27/2012 + " . $minutes . " minutes"));

} //$i = 0; $i < 96; $i++

?>

       </select>

chumpaksome · 07-19-2012, 08:28 PM

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chinikumy · 07-20-2012, 07:54 PM

That seems more like a javascript would help you on that one. Is that how you are trying to do it or purely in PHP? That could also be done Payday loans.

infoleather · 07-31-2012, 04:19 AM

How did you attempt to do this, or purely in PHP?
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mtttt · 09-04-2012, 01:29 AM

It is more simple and quicker to make javascript with jQuery.

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