Need help with array()

Kingdom · 01-02-2011, 08:15 PM

OK, so i have this class:

PHP Code:


			
<?php

class Lang extends Db {

    var $lang = array();

    var $chosen_lang;

    var $lang_dir;

    var $img_dir;

    

    function setLang ($chosen_lang) {

        $this->lang_dir = $_SERVER['DOCUMENT_ROOT'].'/lang/'.$this->chosen_lang.'/';

        $this->img_dir = $_SERVER['DOCUMENT_ROOT'].'/gl_imgs/'.$this->chosen_lang.'/';

        $this->chosen_lang = $chosen_lang;

        

        unset($chosen_lang);

    }

    

    public function loadLang ($file){

        if( file_exists( $_SERVER['DOCUMENT_ROOT'].'/lang/'.$this->chosen_lang.'/'.$file.'.php' ) ) {

            include( $_SERVER['DOCUMENT_ROOT'].'/lang/'.$this->chosen_lang.'/'.$file.'.php' );

            $this->lang[$file] = array();

                

            foreach ($lang as $k => $v) {

                $this->lang[$file][$k] = $v;

            }

        }

        

        unset($lang, $file, $k, $v);

    }

}

?>

And on the index page of the website i have this:

PHP Code:


			
<?php

include($_SERVER['DOCUMENT_ROOT'].'classes/class_Db.php');

include($_SERVER['DOCUMENT_ROOT'].'classes/class_Lang.php');



$lang = new Lang;

$lang->setLang('en-us');

$lang->loadLang('website_account');

$lang->loadLang('website_main-menu');

?>

My question is: why the script won't work if i add the command:

PHP Code:


			
$lang->loadLang('website_main-menu');

If i only leave the following, the script works as intended:

PHP Code:


			
$lang = new Lang; 

$lang->setLang('en-us'); 

$lang->loadLang('website_account');

After some debugging, i found out that the script executes the first loadLang command on the 'website_account', but when it executes the second loadLang command ('website_main-menu'), it freezes at this line on the class:

PHP Code:


			
$this->lang[$file] = array();

Thanks in advance!