Gah.. Regex?

Gareth · 08-26-2008, 08:57 PM

Hi,

If i have a file named something (123).jpg, where 123 is an integer, is there a way where I can get the integer to use in the rest of my script?

I think its regex- not sure though.

Thanks for any help :)

delayedinsanity · 08-27-2008, 12:04 AM

There's a few ways.

basename and explode come to mind.

PHP Code:


			
$file = '/path/to/file/filename.ext';
$file_name = basename($file); // returns "filename"

$file = 'filename.ext';
$file_arr = explode('.', $file);
echo $file_arr[0]; // returns "filename"

Wildhoney · 08-27-2008, 12:05 AM

php Code:

$file = '/path/to/file/filename.ext';
$file_name = pathinfo($file, PATHINFO_FILENAME); // returns "filename"

php Code:

$pFile = (object) pathinfo('/path/to/file/filename.ext');

printf("Directory: %s<br />\n", $pFile->dirname);
printf("Base: %s<br />\n", $pFile->basename);
printf("Extension: %s<br />\n", $pFile->extension);
printf("Filename: %s<br />\n", $pFile->filename);

Gareth · 08-27-2008, 12:18 AM

Thanks, but the problem is I only need part of the filename, specifically the part between the () (but not including them)...

Wildhoney · 08-27-2008, 12:22 AM

php Code:

$pFile = (object) pathinfo('/path/to/file/(123).jpg');
printf("Filename: %s", preg_replace('~[^\d]~i', '', $pFile->filename));

Gareth · 08-27-2008, 12:51 AM

I love you wildhoney- could you explain or point me in the right direction the preg_replace you gave me? Its greek to me (although funnily enough i did actually study greek...)...!

delayedinsanity · 08-27-2008, 12:54 AM

Oh, your file is named 'something(123).jpg' not '123.jpg'.

I misunderstood.
-m

Gareth · 08-27-2008, 01:00 AM

Its my fault, i should have made myself clearer :)

Wildhoney · 08-27-2008, 01:49 AM

All it means is anything that's not an integer (^\d -- ^ being not, and \d meaning digit) should be replaced with null.

Gareth · 08-27-2008, 11:58 AM

Ahh, too easy! Thanks.