str_replace - img

russellharrower · 08-03-2009, 12:00 PM

Hi i need away to strip away the img html and get just the src part of the html image.

Then I need to take the URL to the image and give it a class like

$image=[URL to Image]

then what i want it to do is any other html code like <div> or tables or any HTML code to delete, But all images must be able to get an image class like the one above.

Can any one help me

JaoudeStudios · 08-03-2009, 12:48 PM

server side or client side?

russellharrower · 08-03-2009, 12:53 PM

server side, i believe.

basically i want to take this rss feed http://feedproxy.google.com/OfficialGmailBlog

and then take the images from the post.

JaoudeStudios · 08-03-2009, 01:05 PM

You could do it with a regex, only the images will have a src.

JaoudeStudios · 08-03-2009, 01:07 PM

The php function would be preg_match.

Match src="................"

Village Idiot · 08-03-2009, 02:06 PM

Thats not true, off the top of my head I know it appears in the script and iframe tags.

JaoudeStudios · 08-03-2009, 04:58 PM

Quote:

Originally Posted by Village Idiot

Thats not true, off the top of my head I know it appears in the script and iframe tags.

Yes you are right, sorry I meant within that link. But I am still wrong, it appears in the javascript includes. However, this can all still be filtered out with the regex.

russellharrower · 08-03-2009, 05:13 PM

Can someone give an example?

JaoudeStudios · 08-04-2009, 06:47 AM

I have not tested the below, so it probably wont work, but it will give you a rough idea. Best thing to do is to find an online regex maker - it will allow you to paste some code in and then write your regex and it will match live as you type. ie. http://gskinner.com/RegExr/

PHP Code:


			
$pattern = '@[a-zA-Z0-9_.-]*<img[a-zA-Z0-9_.-]*src="http://www.[a-zA-Z0-9_.-]*"[a-zA-Z0-9_.-]*/>@i';

$subject = '<div id="images"><img src="http://www.jaoudestudios.com/images/image1.jpg" alt="This is an image" /></div>';

preg_match($pattern, $subject, $matches);

sketchMedia · 08-04-2009, 10:55 AM

To get the img src you could use something like this, now baring in mind i'm not the best at regex, so i'm sure Salathe will post with improvements!

PHP Code:


			
<?php
$pattern = '~<img(?:.*)src="(.+?)"(?:.*)\/>~i';
$subject = '<div id="images"><img alt="awd" src="http://www.jaoudestudios.com/images/image1.jpg" alt="This is an image" /></div>';
preg_match($pattern, $subject, $matches);

echo $matches[1];

Now, to match all img src, you need to do thus:

PHP Code:


			
<?php
$pattern = '~<img(?:.*)src="(.+?)"(?:.*)\/>~i';
$subject = '<div id="images"><img alt="awd" src="http://www.jaoudestudios.com/images/image1.jpg" alt="This is an image" /><img alt="awd" src="http://www.jaoudestudios.com/images/image1.jpg" alt="This is an image" /><img alt="awd" src="http://www.jaoudestudios.com/images/image1.jpg" alt="This is an image" /><img alt="awd" src="http://www.jaoudestudios.com/images/imagawdawd1.jpg" alt="This is an image" /><img alt="awd" src="http://www.jaoudestudios.com/images/iawdawd1.jpg" alt="This is an image" /></div>';
preg_match_all($pattern, $subject, $matches);

foreach($matches[1] as $match)
{
     echo '<br />' . $match;
}

Alternitivly, you could use xpath + domdocument:

PHP Code:


			
$subject = '<div id="images"><img alt="awd" src="http://www.jaoudestudios.com/images/image1.jpg" alt="This is an image" /><img alt="awd" src="http://www.jaoudestudios.com/images/image1.jpg" alt="This is an image" /><img alt="awd" src="http://www.jaoudestudios.com/images/image1.jpg" alt="This is an image" /><img alt="awd" src="http://www.jaoudestudios.com/images/imagawdawd1.jpg" alt="This is an image" /><img alt="awd" src="http://www.jaoudestudios.com/images/iawdawd1.jpg" alt="This is an image" /></div>';
$pDom = new DOMDocument();
libxml_use_internal_errors(true);
$pDom->loadHTML($subject);
libxml_use_internal_errors(false);

$pXPath = new DOMXPath($pDom);
$pImgs= $pXPath->evaluate("//img");


foreach($pImgs as $pImg)
{
    echo '<br />' . $pImg->getAttribute('src');
}

russellharrower · 08-04-2009, 11:40 AM

New CODE:

I have come up with a way to post the information

Code:

foreach($pImgs as $pImg)
{
 $imageq = $pImg->getAttribute('src');
 
 $Curl_Session = curl_init('http://www.example.com/cache7/image.php');
 curl_setopt ($Curl_Session, CURLOPT_POST, 1);
 curl_setopt ($Curl_Session, CURLOPT_POSTFIELDS, "imageq=$imageq");
 curl_setopt ($Curl_Session, CURLOPT_FOLLOWLOCATION, 1);
 curl_exec ($Curl_Session);
 curl_close ($Curl_Session);
}

however I am getting this error

Warning: curl_setopt() [function.curl-setopt]: CURLOPT_FOLLOWLOCATION cannot be activated when in safe_mode or an open_basedir is set in /home/example/public_html/image/index.php on line 49

what is this and how do I fix this?

Thanks

Kalle · 08-07-2009, 09:51 PM

Simply, deactivate the horrible safe_mode or disable the open_basedir configuration as the warning says :)