opendir('Y/m/d') ???

Peuplarchie · 11-28-2008, 05:40 AM

Good day to you all,
my question this time seems easy but, I dont have a clue on how to do this...

I would like to read the directory of today...

PHP Code:


			

if ($handle = opendir('Y/m/d,time()')) {

Can somebody help me in wording this ?

Thanks !

Village Idiot · 11-28-2008, 05:44 AM

Try

PHP Code:


			
opendir(date('Y/m/d'));

Peuplarchie · 11-28-2008, 06:14 AM

Thanks but i don't know if it's my function but it don't work :

PHP Code:


			


function compileList($extensions)
{
     if ($handle = opendir(date('Y/m/d')) {
   while (false !== ($file = readdir($handle)))
      {
          $ext = strtolower(end(explode('.', $file)));
       
          if (in_array($ext, $extensions) AND $file != "." AND $file != "..")
              {
                  $files[$file]=implode(file($file));
              }
       }
  closedir($handle);
  }
  
if (empty($files))
{

    return null;
}
return $files;  
}

it give me an error on line tree..

Parse error: syntax error, unexpected '{'

zxt3st · 11-28-2008, 09:06 AM

Just a quick overview on your code.

PHP Code:


			
while (false !== ($file = readdir($handle)))

I dont think if there is an "!==" operator ever exist in php. Check in here PHP Operators

Tanax · 11-28-2008, 10:46 AM

Yes there is:
PHP: Comparison Operators - Manual