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Old 11-17-2008, 01:17 AM   #1 (permalink)
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Application Break if no file found in directory

Good day to you,
I have a function which return an array of files.
I would need it to break if there is no file in the directory.

Here is the code :
PHP Code:
function compileList($extensions)
{
     if (
$handle opendir('.')) {
   while (
false !== ($file readdir($handle)))
      {
          
$ext strtolower(end(explode('.'$file)));
       
          if (
in_array($ext$extensions) AND $file != "." AND $file != "..")
              {
                  
$files[$file]=implode(file($file));
              }
       }
  
closedir($handle);
  }
  return 
$files;
         

Thanks !
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Old 11-17-2008, 02:22 AM   #2 (permalink)
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How about something like this? Would this do the job for you?

php Code:
function get_files_by_extension($szDirectory, array $aExtensions)
{
    $szExtensions = vsprintf('*.%s', implode(',*.', $aExtensions));
    $szGlob = sprintf('%s/{%s}', rtrim($szDirectory, '/'), $szExtensions);
    return glob($szGlob, GLOB_BRACE | GLOB_NOSORT);
}

print_r(get_files_by_extension('myDirectory', array('php', 'ico', 'gif')));
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Old 11-17-2008, 02:31 AM   #3 (permalink)
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Thanks for that pice of code...but it is too much for what I needed...
here's:
PHP Code:
if (empty($files)) 

    echo 
'No results'
    return 
null

return 
</span></span>
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