List only some extention (File Listing)

Peuplarchie · 11-09-2008, 08:15 PM

Good day to you all,
I'm working on a pice of code which list all files in a directory and return the list and its content right under the name of the file.

PHP Code:


			

<?php
$thelist = "";
 if ($handle = opendir('.')) {
   while (false !== ($file = readdir($handle)))
      {
          if ($file != "." && $file != "..")
      {
              $thelist .= '<a href="'.$file.'">'.$file.'</a><br/>';
            $contents = file($file);
            $string = implode($contents);
            $thelist .= '<p>'.$string.'</p>';
            
          }
       }
  closedir($handle);
  }
?>
<P>List of files:</p>
<P><?=$thelist?></p>

I'm looking for a way of choose only 3 or 4 extension only.

How would I dow so ?

Thanks !

Runar · 11-09-2008, 11:21 PM

I quite recently learned that glob() is the way to do this. The function will find pathnames matching a pattern (according to the manual) and works perfectly as a replacement for opendir() and all those functions.

PHP Code:


			
<?php



// Turn on error reporting

ini_set( 'display_errors', 'yes' );



// Set path to our directory (for easier use)

// Remember the last slash (/)!

$directory_path = 'your/folder/';



// Return .png files found in the directory

foreach( glob( $directory_path . '{ *.file1, *.file2, *.file3 }', GLOB_BRACE ) as $file )

{

    // Put some file data in variables

    $name = basename( $file );

    $size = filesize( $file );

    $file = implode( file( $file ) );

    

    // Do your thing, for example add the info to an array

    // or output it directly

    // $files[]  = array( 'name' => $name, 'size' => $size, 'content' => $file );

}

    

?>