external data into a text file

Seraskier · 04-18-2008, 02:03 AM

ok, so dont ask why, just trying something....

I am wanting to put that actual data into a text file and using fwrite to go to the end and add the data in.

But I seem to not be able to get the data into an array.

array.txt

Code:

'1'=>array
	(
		'xxxxx@xxxxxxxx.xx.xxx',
		'xxxxxxxxx'
	),
	
'2'=>array
	(
    	'xxxxx@xxxxxxx.xxx',
		'xxxxxx'
	),

users.php

Code:

<?php
///////////////////////////////////////
//gets the id inputed by the user    //
$id=$_GET['id'];                     //
	                            //
//initializes the array              //
$users=array();                      //
                                     //
//shortcut for data in the array     //
$users=$users[$id];                  //
///////////////////////////////////////

//Beginning of the profile code
echo "Email Address: <b>".$users[0]."</b>";
echo "<br />Username: <b>".$users[1]."</b>";
//And, the ending of the profile code

//just here to test something (temporary)
echo "<br /><br />";
echo "<b>We have ".count($users)." registered users.";
?>

I took out the code that I used to try to read the array.txt, doesnt work.

I cant seem to get it to work and I cant find anything online.

Jordan

Seraskier · 04-18-2008, 02:18 AM

found it out, its a little different, but it works:

Code:

//initializes the array
$users=array();
//populates the array
require_once('array.php');

any other better ideas would be great!

Wildhoney · 04-18-2008, 02:32 AM

I'm quite unsure of what you're asking, but have you tried the serialize and unserialize functions? If you're also asking how to read and write, I think I have covered everything you may need to know in the code below.

php Code:

$aItems = array();
$szFile = 'items.txt';

if(file_exists($szFile))
{
    $szContent = file_get_contents($szFile);
    $aItems = unserialize($szContent);
}

$aItems[] = array
(
    'Name' => 'Adam',
    'Email' => 'adam@example.com'
);

file_put_contents($szFile, serialize($aItems));
printf('Items in file: %d', count($aItems));

Seraskier · 04-18-2008, 03:00 PM

I know how to edit the file and add stuff to it, I just need a way to populate an array from another file....

Wildhoney · 04-18-2008, 07:08 PM

Serialize and unserialize will do that all for you.

Seraskier · 04-18-2008, 10:32 PM

ill try to explain better....

i have a register form, they put in all their info and then php processes it and then uses fopen() and fwrite() it will add their information into a text file (using a text file it would be easier to edit becuase i would need a ); at the end that fwrite() cant edit before that) and then use php to make a new array of $users [$users=array();] and then populate the array with a text document, so i would want it to.

i can populate the array using php by using php

Code:

index.php
----------------------------------------
$users=array();
require_once('users.database.php');
$users=$users[$id]; //for shortcut purposes

########################################
users.database.php
----------------------------------------
$users[1]=array('test@test.com','testAccount','testPassword');
$users[2]=array('test@test2.com','testAccount2','testPassword2);
//end of user arrayed database

if i was to use count($users) or count(count_keys($users)) it would return 3 instead of 2, i am trying to use count() for counting users, but it counts the email address, username, and password for keys instead of the number inside [] in '$users[1]=array(...);'...
so if i used:

Code:

'1'=>array
     (
          'test@test.com' //email address
          'testAccount' //username
     )

and using count() or count(count_keys()) it would return 1 instead of 2, but that being in a text file i cant get it to populate the array

hope that helps explain my situation

flyingbuddha · 04-19-2008, 01:13 PM

Can't you call the two $users variables something different to avoid confusion? Sounds like php is struggling to distinguish which var you're trying to count.

Seraskier · 04-20-2008, 05:04 AM

Quote:

Originally Posted by flyingbuddha

Can't you call the two $users variables something different to avoid confusion? Sounds like php is struggling to distinguish which var you're trying to count.

What do you mean?