since last update

talonos · 08-17-2009, 02:50 PM

i'm trying to make a script and cant get any of them working

say i have a string:

PHP Code:


			
$lastupdate = "2009-08-10 21:10:52";

from that i want to omit the 21:10:52 (time)

then calculate how many days have past and display it as

PHP Code:


			
echo " ' .$days. ' days since last update";

any help with this would be greatly appreciated

Talonos

JaoudeStudios · 08-17-2009, 02:54 PM

$date = substr($lastupdate, 0, 10); // will remove the time
$date_ = explode('-', $date);
$day = $date[2];

This is not ideal. What version of php are you running. The latest version (php 5.3) has some very cool and easy to use date manipulation functionality. Or you could use Zend_date to achieve the same. Else I would convert it to a unix time stamp and do the calculation from there.

talonos · 08-17-2009, 03:57 PM

my PHP Version is 5.2.10 and i cant update it :(

also your script works perfect m8 with a few adaptations :)

JaoudeStudios · 08-17-2009, 05:04 PM

Cool, glad it worked :)

ETbyrne · 08-17-2009, 06:15 PM

If you are using PHP 5.2 or better then you can use most of the DateTime functions:

PHP Code:


			
$date = new DateTime('2009-08-10 21:10:52');
echo $date->format('Y-m-d'); // Output 2009-08-10

Check out these links

> http://us.php.net/manual/en/class.datetime.php
> http://us.php.net/manual/en/datetime.format.php
> http://us.php.net/manual/en/datetime.modify.php

JaoudeStudios · 08-17-2009, 06:28 PM

Really? I thought that was only in php5.3 and above?

ETbyrne · 08-17-2009, 06:30 PM

Check the links I gave to the docs. Only some of the DateTime functions require PHP 5.3. I'm running PHP 5.2.9 right now on my local box and it works perfectly.