hi

MY SCRIPT STAND ON THIS
FOR NOW I DONT CARE ABOUT SECURITY THATS WILL COME LATER
here is another problem that i had in my news script

here is the code

but the cookie douesnt register and it gaves this error
so whats the problem !!

Hi,

This message means that your script has already output something before the cookie information is sent.

Often this is caused by a notice/warning that PHP is sending. Try putting:

as the very first line of your script and see if PHP then shows the errors.

Also, check that config.php isn't sending any output (even a blank space/line) and make sure that "display_errors" is set to true in your php.ini (if you have access to it)

Alan

here is the error when i added error_reporting(E_ALL)

and i think the config.php is fine

You can fix the constant notices by altering the $_POST references to $_POST['user'], $_POST['pass'] and so on.

The cannot modify header information is caused that you printed something out before sending an HTTP header. This can be fixed by either removing all output being printed above that code. (Tip from experince i sometimes came to add an extra space or newline after my ending ?> which caused these warnings). Or you can use output buffering functions to fix this.

To fix this using output buffering, then add ob_start() to the very start of you script, and ob_end_flush() to the very end and it should work alright.

Hope this helps,
Kalle

the script become like that right
but it gaves error

You forgot the ending ; after ob_start() and ob_end_flush() function calls =)

ob_start();
ob_end_flush();

Sorry that I wasn't very clear with that, Just thought you added them yourself =P

You don't have a column after ob_start, and neither do you after ob_end_flush. Correct that and it should work fine.

__________________

when i add a column like that =>
ob_start(members) ;

it gaves this error

lol sorry i was so happy that it can be the solution so i was in rush i didnt think lol sorry again
but anyway it didnt work here is the script online =>

http://81.192.223.238/news/login.php

username = aze password = aze

Are you calling ob_start() with a parameter now? Because you shouldn't unless you use an output handler. And you're error is very odd as ob_end_flush() doesn't take any parameters.

i didnt gave it any parameter in the first time
just xenon who told me that :d

try this please to see the error

http://81.192.223.238/news/login.php

up
up
up!!

don't be inpatient...
don't be inpatient...
don't be inpatient!!

First off, your page does NOT open, so I can't help you on that side.

Try this one, and first off, you need to improve your scriptskill because it's a damn mess. Sorry, but at first it was like finding a needle in a haystack ... and no, in_array didn't work.

__________________

"Life is a bitch, take that bitch on a ride"

respawn about the link it wont work bcz i put wamp offline now
about the mess lol , im a begginer , u have any good suggesions about order
and that code that u gave me
it didnt work

and im patient lol

Please, if code does not work for you, give everyone some details. At the very least, copy and paste any error message(s). We can't help if all you give us is "it didnt work".

here is the errors =>

that script make me very mad

Please take the time to read through, and act on, all of the information made available to you in this topic. The Notice errors that you're getting have already been identified and a solution given to you earlier in the topic (thanks Kalle). You should not use $_POST[name] unless name is defined as a constant in your script (which is isn't, and you shouldn't!). To access the name item in the $_POST array, you need to use: $_POST['name']. Note the single quotes around name.

The final three Warnings are because PHP sent output to the page already: the Notice errors.

thanks buti tried it and the same problem