how to $_POST this?

meshi · 12-19-2007, 02:45 PM

if i have a code like this:

PHP Code:


			
for($i=0;$i<3;$i++){

echo '<input type="submit" name="submit'.$i.'" value='.$i.'>';

}

if (isset($_POST["submit$i"])){<--------this is not correct.

do the following

}

how would i post for name that is incremented?

bdm · 12-19-2007, 02:51 PM

I do believe that you would need a second loop which would wrap your if statement.

And I'm not positive about $i's scope, but I don't think you can call $i outside of your for loop.

Tanax · 12-19-2007, 03:01 PM

Quote:

Originally Posted by bdm

I do believe that you would need a second loop which would wrap your if statement.

And I'm not positive about $i's scope, but I don't think you can call $i outside of your for loop.

Correct.
He must create another loop inside his if statement

bdm · 12-19-2007, 03:03 PM

Quote:

Originally Posted by Tanax

Correct.
He must create another loop inside his if statement

You mean a for loop wrapping his if statement.

Tanax · 12-19-2007, 03:26 PM

Quote:

Originally Posted by bdm

You mean a for loop wrapping his if statement.

lol, woops

yea

ReSpawN · 12-19-2007, 03:10 PM

Yes, initializing the same, twice, isn't possible. (edit, you CAN reset a counter with the reset(); command)

PHP Code:


			
<?php

/**
 * @author ReSpawN
 * @copyright 2007
 */

    $count = 3;
    for($i = 0; $i <= $count; $i++){
        echo '<input type="submit" name="submit'.$i.'" value="Submit'.$i.'" />';
    }
    
    if (isset($_POST['submit'])) {
        echo $_POST['submit'].' has been set.';
    }  
    
?>

meshi · 12-20-2007, 04:33 PM

sori i think a little confuse here

PHP Code:


			
for($i=1;$i<4;$i++){ 

echo '<input type="text" name=="a'.$i.'" value='.$i.'><input type="submit" name="submit'.$i.'" value="Submit">'; 

} 

if (isset($_POST["submit$i"])){<--------this is not correct. 

echo $_POST["a$i"];

}

the code iterpretation above is this
1 Submit
2 Submit
3 Submit
what i want is to display the value of the textbox.how can i
display its value?when its submit button hit?

xenon · 12-20-2007, 06:25 PM

Perhaps because the if( $_POST['submit$i] ) is always checking $_POST[submit4]. You may want to put the submit button into a form control before expecting to have a $_POST in the first place. If you're generating all the 4 buttons in the same form, note that only one button will be available at a given point (e.g.: you can't set all the 4 post buttons to be available after posting the form).

Wildhoney · 12-20-2007, 07:30 PM

How about either creating an array of fields, like so:

html4strict Code:

<input type="text" name="textbox[]" />
<input type="text" name="textbox[]" />
<input type="text" name="textbox[]" />

Or using a foreach loop on the POST? Like this:

php Code:

foreach($_POST as $szKey => $szValue)
{
    if(preg_match('~^submit~i', $szKey))
    {
        echo 'Set';
    }
}

Salathe · 12-20-2007, 07:37 PM

To summarise the comments saying to use a second for loop, here's a visual example.

PHP Code:


			
// First loop, to output the form elements

for ($i = 1; $i <= 3; $i++)

{ 

    printf('<input type="text" name="a%d" value="%d" /><input type="submit" name="submit%d" value="Submit" />', $i, $i, $i);

    // or, see: http://www.talkphp.com/showthread.php?t=1129

    // printf('<input type="text" name="a%1$d" value="%1$d" /><input type="submit" name="submit%1$d" value="Submit" />', $i);

} 



// Second loop, to respond if the form was posted

for ($i = 1; $i <= 3; $i++)

{

    // Alternative: isset($_POST['submit' . $i])

    if (array_key_exists('submit' . $i, $_POST))

    {

        echo $_POST['a' . $i];

    }

}

meshi · 01-08-2008, 10:23 AM

thanks guys..i understand now