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Old 09-29-2007, 07:59 PM   #1 (permalink)
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How can I check with PHP if a table in the database exists? :confused: :confused:
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Old 09-29-2007, 09:03 PM   #2 (permalink)
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Quote:
Originally Posted by Haris View Post
PHP Code:
        public function __construct(){
            
$szSQL "CREATE TABLE IF NOT EXISTS ...";
        } 
"CREATE TABLE IF NOT EXISTS" is the key phrase!
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Old 09-29-2007, 10:39 PM   #3 (permalink)
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But I don't want to create a table if it doesn't exists, I just want to check if it exists :(
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Old 09-29-2007, 11:24 PM   #4 (permalink)
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PHP Code:
$pTables mysql_list_tables('myDatabase');

while(
$aTable mysql_fetch_row($pTables))
{
    if(
$aTable[0] == 'myTable')
    {
        echo 
'Found!';
        break;
    }

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Old 09-29-2007, 11:50 PM   #5 (permalink)
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The mysql_fetch_row function was depreciated a long time ago. It's better to do a normal query and check the result:

PHP Code:
if(!mysql_num_rows(mysql_query("SHOW TABLES LIKE 'myTable';")))
{
    echo 
'Table myTable does not exist.';

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Old 09-30-2007, 09:52 AM   #6 (permalink)
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Yea, it worked :D Thanks guys!
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