TalkPHP - Confused within forms

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Confused within forms

PHP Code:


		
			
while($row = mysql_fetch_array($sql)){
    $qID = $row['id'];
    echo "<b>Question ID#</b>".$row['id']." - ".$row['question']."?";
    echo "<br><b>1st Choice:</b> $row[choice_1]";
    echo " - <b>2nd Choice:</b> $row[choice_2]";
    echo " - <b>3rd Choice:</b> $row[choice_3]";
    echo " - Edit Choices:<input type=\"radio\" name=\"edit_choices\" value=\"".$qID."\"><br/>";
    echo "Delete:<input type=\"checkbox\" name=\"selected_question_array[]\" value=\"".$qID."\">";
    echo " - Edit:<input type=\"radio\" name=\"selected_edit_question\" value=\"".$qID."\"><br/>";
    echo "<br />";
}
echo "<input type=\"submit\" name=\"delete\" value=\"Delete Question\">";
echo "<input type=\"submit\" name=\"edit\" value=\"Edit Question\">";
echo "<input type=\"submit\" name=\"edit_choice\" value=\"Edit Choice\">";
echo "</form>";

The above form renders like:

Question ID#1 - Question here
1st Choice: For - 2nd Choice: Against - 3rd Choice: No choice - Edit Choices:radiobox

Question ID#2 - Question here
1st Choice: For - 2nd Choice: Against - 3rd Choice: No choice - Edit Choices:radiobox

Question ID#3 - Question here
1st Choice: For - 2nd Choice: Against - 3rd Choice: No choice - Edit Choices:radiobox
Delete: checkbox - Edit: radiobox

Delete Button Edit Button Edit Choices Button

The delete button works perfectly. However when an question or a question choices are selected to be edited from the radio boxes. It doesn't shows the results in the end.

delete_edit_questions.php file:

PHP Code:


		
			
<?php

// Last Modified 18th August 2007

ob_start();
session_start();

include('templates/header.php'); // Header template
include('../config/config.php'); // Includes configuration files
include('../lib/functions.php'); // Load all functions from Library

if(!session_is_registered("username")){
header('Location: index.php');
exit();
}
else {

$submit_delete = $_POST['delete'];
if(isset($submit_delete)){

$sql = mysql_query('SELECT * FROM questions') or die(mysql_error());

$selected_question = $_POST['selected_question_array'];
foreach ($selected_question as $qID){
    mysql_query("DELETE FROM questions WHERE id='$qID'") or die(mysql_error());
    mysql_query("DELETE FROM answers WHERE question_id='$qID'") or die(mysql_error());
    echo "Questions <b>".$qID."</b> deleted!<br/>";
}

}

elseif(isset($_POST['edit_choice'])){
    $edit_choice_qID = $_POST['edit_choices'];
    echo "<form method=\"POST\" name=\"choices\">";
    echo "First Choice(Positive): <input type=\"text\" name=\"choice_1\"><br>";
    echo "Second Choice(Negative): <input type=\"text\" name=\"choice_2\"><br>";
    echo "Third Choice(Any): <input type=\"text\" name=\"choice_3\"><br>";
    echo "<input type=\"hidden\" value=\"".$edit_choice_qID."\" name=\"edit_choices_qID\">";
    echo "<input type=\"submit\" name=\"submit_new_choices\" value=\"Edit\">";
    echo "</form>";
    if(isset($_POST['submit_new_choices'])){
        echo $_POST['choice_1'];
    }
}

elseif(isset($_POST['edit'])) {
    $submit_edit = $_POST['edit'];
    $edit_qID = $_POST['selected_edit_question'];
    echo "<form method=\"POST\" name=\"questions\">";
    echo "Enter new question: <input type=\"text\" name=\"new_question\">";
    echo "<input type=\"hidden\" value=\"".$edit_qID."\" name=\"selected_edit_q\">";
    echo "<input type=\"submit\" name=\"submit_new_question\" value=\"Edit\">";
    echo "</form>";
    $submit_new_question = $_POST['submit_new_question'];
    $new_question = $_POST['new_question'];
    $edit_ID = $_POST['selected_edit_q'];
    if(isset($submit_new_question)){
        mysql_query("UPDATE questions SET question='$new_question' WHERE id='$edit_ID'") or die(mysql_error());
        echo "Question successfully changed to ".$new_question;
    }
}

include('templates/footer.php'); // Footer Template

}

?>

I think I'm lost between the forms, please help. I think I'm wrong with the elseif conditional statements.

Could you be a bit more specific as to what isn't working? So for example, say I select a question and then select edit choices. Are you saying that it isn't showing the data for the choices? If so, then that will be cause you need to get that data from the database using the ID you've passed through $_POST['edit_choices'].

On another note, there are also a few variable assignments to $_POST variables that have not been validated. This is generally a bad idea, but for simplicity, you could just ignore the error using @. Here are the ones I noticed:

1 near the top:

$submit_delete = @$_POST['delete'];

and these 3 near the bottom:

$submit_new_question = @$_POST['submit_new_question'];
$new_question = @$_POST['new_question'];
$edit_ID = @$_POST['selected_edit_q'];

Quote:

Originally Posted by Karl (Post 2110)

Hmm, what I want to do is that when someone selects the checkbox to either edit the question or edit the choices for the question. The admin is redirected to edit questions or the choices.

In the delete_edit_questions.php, there are forms for both of the cases.

Edit_choice case

PHP Code:


		
			
elseif(isset($_POST['edit_choice'])){
    $edit_choice_qID = $_POST['edit_choices'];
    echo "<form method=\"POST\" name=\"choices\">";
    echo "First Choice(Positive): <input type=\"text\" name=\"choice_1\"><br>";
    echo "Second Choice(Negative): <input type=\"text\" name=\"choice_2\"><br>";
    echo "Third Choice(Any): <input type=\"text\" name=\"choice_3\"><br>";
    echo "<input type=\"hidden\" value=\"".$edit_choice_qID."\" name=\"edit_choices_qID\">";
    echo "<input type=\"submit\" name=\"submit_new_choices\" value=\"Edit\">";
    echo "</form>";
    if(isset($_POST['submit_new_choices'])){
        echo $_POST['choice_1'];
    }
}

Edit question case:

PHP Code:


		
			
elseif(isset($_POST['edit'])) {
    $submit_edit = $_POST['edit'];
    $edit_qID = $_POST['selected_edit_question'];
    echo "<form method=\"POST\" name=\"questions\">";
    echo "Enter new question: <input type=\"text\" name=\"new_question\">";
    echo "<input type=\"hidden\" value=\"".$edit_qID."\" name=\"selected_edit_q\">";
    echo "<input type=\"submit\" name=\"submit_new_question\" value=\"Edit\">";
    echo "</form>";
    $submit_new_question = $_POST['submit_new_question'];
    $new_question = $_POST['new_question'];
    $edit_ID = $_POST['selected_edit_q'];
    if(isset($submit_new_question)){
        mysql_query("UPDATE questions SET question='$new_question' WHERE id='$edit_ID'") or die(mysql_error());
        echo "Question successfully changed to ".$new_question;
    }
}

Well, after they've entered the desired values in the text field to either edit the choices or the question, the values update the database and returns echo but it's not working. After submitting the form, nothing displays.

Ok, seems like you've got yourself in a muddle, try the following:

Find the line:

PHP Code:


		
			
echo "<input type=\"hidden\" value=\"".$edit_choice_qID."\" name=\"edit_choices_qID\">";

and replace it with:

PHP Code:


		
			
echo "<input type=\"hidden\" name=\"edit_choice\">";
echo "<input type=\"hidden\" value=\"".$edit_choice_qID."\" name=\"edit_choices\">";

See if that fixes the edit choices part of the script.

Yeah, it fixed it. Why? :O

The reason why is because when you first submit the form you send two specific POST vars along with it, edit_choices (containing the ID) and edit_choice, which you used to specify the action.

However, on the edit choice page you didn't resend the edit_choice or edit_choices when you resubmitted the form, therefor the following condition failed:

PHP Code:


		
			
elseif(isset($_POST['edit_choice'])){

So, what I did was resend edit_choice as a hidden var and changed edit_choices_qID to edit_choices - the second change fixed the following assignment:

PHP Code:


		
			
$edit_choice_qID = $_POST['edit_choices'];

You've also got similar problems with the edit questions part of the script. Try this fix:

Replace the following line:

PHP Code:


		
			
echo "<input type=\"hidden\" value=\"".$edit_qID."\" name=\"selected_edit_q\">";

with this line:

PHP Code:


		
			
echo "<input type=\"hidden\" value=\"".$edit_qID."\" name=\"selected_edit_question\">";

and then replace this line:

PHP Code:


		
			
$edit_ID = @$_POST['selected_edit_q'];

with this line:

PHP Code:


		
			
$edit_ID = $edit_qID;

In reality that last replacement isn't needed, instead you should replace all occurences of $edit_ID with $edit_qID. However, either way will work.