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Salathe · 01-18-2008, 06:47 PM

Well, json_encode will only return "null" in two cases:

If the argument passed in was NULL.
If the argument passed is not JSON encodable.

Therefore, a quick check for errors might be something along the lines of the following :

PHP Code:


			


    // Suppress E_WARNING error if any. 

    $szJson = @json_encode($szContent);



    // If the encoded string is "null" but we didn't pass in NULL

    // then throw the exception.

    if ($szJson === 'null' AND $szContent !== NULL)

    {

        throw new Exception(sprintf(

            'Unable to encode "%s" into JSON format.',

            gettype($szContent)

        ));

    }

01-18-2008, 06:47 PM	#10 (permalink)
Salathe Moderateur Join Date: Apr 2007 Posts: 1,393 Thanks: 5	Well, `json_encode` will only return `"null"` in two cases: If the argument passed in was `NULL`. If the argument passed is not JSON encodable. Therefore, a quick check for errors might be something along the lines of the following : PHP Code: `// Suppress E_WARNING error if any. $szJson = @json_encode($szContent); // If the encoded string is "null" but we didn't pass in NULL // then throw the exception. if ($szJson === 'null' AND $szContent !== NULL) { throw new Exception(sprintf( 'Unable to encode "%s" into JSON format.', gettype($szContent) )); }`