@webtuto

the % procent means that it replaces "anything" so for example you want to find a name ending with "Harrison" and you would search for "%Harrison". See the % in the beginning ?

Switch place of the % if you want to search for the name beginning with "Harrsion" as so "Harrison%". Catching on now ?

And if you want to search for a name containing "Harrison" then it would be "%Harrison%".

I belive you can use a ? questionmark for replacing a single char.
Correct me if im out on a limb here ?

And see Wildhoney and bluesaga´s post above.

I had trouble with the LIKE thing in my early days of MySQL queries to.

Good Luck.

/EyeDentify

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