TalkPHP - View Single Post - The most inventive way to switch 2 values

TlcAndres · 01-04-2008, 09:41 PM

I made this...then read the rules, I broke the majority of the rules

PHP Code:


			


<?

    $a = 1;

    $b = 2;    

    preg_match_all('/[1-9]/',serialize(array($a,$b)),$ar);

    $ar = reset($ar);

    foreach(array_keys($ar) as $k)

    {

        $r = next($ar);

        if(empty($ar[$k]) or $ar[$k] == $r)

        {

            unset($ar[$k]);

        }

        else

        {

            $a = $ar[$k];

            $a = ($a) + (40 / 2 - 10 * .5 - 5.5 * 2 << 5.5 >> 10);

            $ar[$k] = $a;

        }

    }

    $r = array_reverse(array_splice($ar,1));

    $let = 'a';

    while(list(,$v) = each($r))

    {

        $string .= chr(36) . $let . chr(61) . $v . chr(59);

        ++$let;

    }

    ob_start();

    eval($string);

    ob_get_clean();

    var_dump($a);

    var_dump($b);

?>

It was still fun though

(I know, nearly everything there is useless)

01-04-2008, 09:41 PM	#9 (permalink)
TlcAndres The Addict Join Date: Nov 2007 Posts: 264 Thanks: 2	I made this...then read the rules, I broke the majority of the rules PHP Code: <? $a = 1; $b = 2; preg_match_all('/[1-9]/',serialize(array($a,$b)),$ar); $ar = reset($ar); foreach(array_keys($ar) as $k) { $r = next($ar); if(empty($ar[$k]) or $ar[$k] == $r) { unset($ar[$k]); } else { $a = $ar[$k]; $a = ($a) + (40 / 2 - 10 * .5 - 5.5 * 2 << 5.5 >> 10); $ar[$k] = $a; } } $r = array_reverse(array_splice($ar,1)); $let = 'a'; while(list(,$v) = each($r)) { $string .= chr(36) . $let . chr(61) . $v . chr(59); ++$let; } ob_start(); eval($string); ob_get_clean(); var_dump($a); var_dump($b); ?> It was still fun though (I know, nearly everything there is useless)