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Old 01-02-2008, 04:08 PM   #1 (permalink)
TlcAndres
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Join Date: Nov 2007
Posts: 264
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Default eval - seperate instace.

Does eval() create a seperate parsing instance? to clear up the question are any variables function and classes not available within the eval() function? the reason I ask is because out of curiosity I created this...

PHP Code:
public function __call($funcName,$args)
        {
            
$classArr = array(
                    
'm_' => 'member',
                    
't_' => 'template',
                    
'f_' => 'file',
                    
'u_' => 'upload',
                    
'd_' => 'mysql'
                
);
            
$class substr($funcName,0,2);
            
$func str_replace($class,'',$funcName);
            
$func preg_replace('$\\((.*?)\\)$','',$func);
            
$order $classArr[$class];
            if(!empty(
$order))
            {
                for(
$i=0;$i func_num_args();++$i)
                {
                    
$argList .= func_get_arg($i) . ',';
                }
                
                
$c substr($argList,strlen($argList) -1,1);
                if(
$c == ',')
                {
                    
$argList substr($argList,0,strlen($argList) -1);
                }
                
$string sprintf('$this->%s->%s(%s);',$order,$func,'o');
                echo 
$string;
                
ob_start();
                eval(
$string);
                
$ret ob_get_clean();
                return 
$ret;
            }
        } 
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