12-13-2007, 07:05 PM
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#4 (permalink)
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Moderateur
Join Date: Apr 2007
Posts: 1,381
Thanks: 5
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As an aside, you don't need to do date('z', strtotime(date('Y-m-d H:i'))) to get today's day of the year. Simply skip the second argument to use the current time stamp: date('z').
Personally, I'd prefer working with the timestamps themselves and only use the date() function for outputting friendly strings. Something like the the following:
php Code:
<?php$iDateStart = 1195958278; // expiry = starting timestamp + 90 days (in seconds)$iDateExpire = $iDateStart + (90 * 24 * 60 * 60); // Days left = difference between timestamps in seconds (expiry - now)// divided by number of seconds in a day (86,400)// Use floor() to round down to the day.$iDaysLeft = floor(($iDateExpire - time()) / (24 * 60 * 60)); // Output:// There are 71 days left until 2008-02-23 02:37.printf('There are %d days left until %s.', $iDaysLeft, date('Y-m-d H:i', $iDateExpire));
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