TalkPHP - View Single Post - Most efficient way of playing with dates?

bdm · 12-13-2007, 07:07 PM

So I've got this unix timestamp from the past which I needed to convert into a date:

PHP Code:


			
$firstDate = date('Y-m-d H:i', 1195958278);

Next I added 90 days:

PHP Code:


			
$expiry = date('Y-m-d H:i', strtotime('+90 day', $firstDate));

This is because each pass is valid for 90 days after the first date. I then proceed by figuring out how many days are left for the pass to expire:

PHP Code:


			
$daysLeft = 365 - (date('z', strtotime(date('Y-m-d H:i'))) - date('z', strtotime($expiryDate)));

I've tested it with a bit of data and it seems to work.

Does anyone see something totally wrong? Or maybe an easier alternative?

Thank you.

12-13-2007, 07:07 PM	#1 (permalink)
bdm The Acquainted Join Date: Nov 2007 Posts: 127 Thanks: 14	Most efficient way of playing with dates? So I've got this unix timestamp from the past which I needed to convert into a date: PHP Code: `$firstDate = date('Y-m-d H:i', 1195958278);` Next I added 90 days: PHP Code: `$expiry = date('Y-m-d H:i', strtotime('+90 day', $firstDate));` This is because each pass is valid for 90 days after the first date. I then proceed by figuring out how many days are left for the pass to expire: PHP Code: `$daysLeft = 365 - (date('z', strtotime(date('Y-m-d H:i'))) - date('z', strtotime($expiryDate)));` I've tested it with a bit of data and it seems to work. Does anyone see something totally wrong? Or maybe an easier alternative? Thank you.