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Wildhoney · 12-07-2007, 09:03 PM

In extension to Karl's, consider this:

php Code:

$a = 1;
$b =& $a;
$b = 2;

In the above example, both $a and $b now equal 2 because $b has been set as a reference to $a and so whatever $b becomes, $a becomes as well.

In a more complicated example:

php Code:

$aArray = array('Apple', 'Orange', 'Kiwi', 'Pear');
$pItem =& $aArray[2];
$pItem = 'Pitaya';

As $pItem is now a reference to the third item in our array, changing its value will also change the value in the array, so Kiwi now becomes Pitaya.

12-07-2007, 09:03 PM	#10 (permalink)
Wildhoney La Vida es Sueño Join Date: Sep 2007 Location: Oldham Posts: 2,280 Thanks: 90	In extension to Karl's, consider this: php Code: $a = 1; $b =& $a; $b = 2; In the above example, both `$a` and `$b` now equal 2 because `$b` has been set as a reference to `$a` and so whatever `$b` becomes, `$a` becomes as well. In a more complicated example: php Code: $aArray = array('Apple', 'Orange', 'Kiwi', 'Pear'); $pItem =& $aArray[2]; $pItem = 'Pitaya'; As `$pItem` is now a reference to the third item in our array, changing its value will also change the value in the array, so Kiwi now becomes Pitaya. __________________ The man who comes back through the Door in the Wall will never be quite the same as the man who went out.