10-13-2007, 11:50 PM
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#3 (permalink)
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The Acquainted
Join Date: Sep 2007
Posts: 126
Thanks: 4
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Quote:
Originally Posted by Salathe
Although you might not think the same, your post is really very vague and lacking details. Post up your code, or a succinct sample, and it'll be ten times easier to provide exactly what you want.
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Ok, right now I have a button with the following link: javascript :createFileInput();
The js createFileInput function:
PHP Code:
//** FUNCTION: Create Upload Form
function createFileInput(path) {
var tbody = document.getElementById('list_body').getElementsByTagName('tbody')[0];
// Create Table Row
var tr = document.createElement("tr")
if (bg_color) { tr.className="on"; bg_color= false; } else { bg_color = true;}
// Create Table Cell
var td = document.createElement("td")
td.id='upload_'+count;
td.width='100%';
var output = new Array();
output.push("<form id='frmUpload_"+count+"' target='uploadForm' method='post' enctype='multipart/form-data' action='/cgi-bin/upload.cgi?sid="+sid+"'>");
output.push("<input type='hidden' name='path' value='"+path+"'>");
output.push("<input style='width:100%;' type='file' name='filename' ><\/form>");
td.innerHTML = output.join('');
tr.appendChild(td);
tbody.appendChild(tr);
uploads.push(count);
if (count != 0 ) {
var tiggerForm = document.getElementById('frmUpload_'+count);
tiggerForm['filename'].click();
tiggerForm = null;
}
count++;
}
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