11-08-2009, 05:07 PM
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#5 (permalink)
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The Wanderer
Join Date: Nov 2009
Location: Denmark
Posts: 5
Thanks: 1
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try changing
PHP Code:
mysql_query($sql);
to
PHP Code:
mysql_query($sql) or die(mysql_error());
what does that output?
and as adamdecaf said, the code can easily be injected
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