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ioan1k · 08-27-2009, 01:42 PM

Are you send the header information before echoing the binary data?

You will need to send out the following headers.

php Code:

header('Content-type: image/png;');
header('Content-length: $iamgesize);

So you code will appear something like

php Code:

$data = mysql_query('SELECT data, filesize FROM images WHERE imageId = 1');
$data = mysql_fetch_assoc($data);
header('Content-type: image/png;');
header('Content-length: '.$data['filesize'].'');
echo $data['data'];

You cannot print out the data with other html content and must load the images through a php file, for example

html Code:

<div id="user">
    <img src="load-image.php?id=23" alt="Image" />
</div>

08-27-2009, 01:42 PM	#4 (permalink)
ioan1k The Contributor Join Date: Mar 2009 Location: US Posts: 76 Thanks: 0	Are you send the header information before echoing the binary data? You will need to send out the following headers. php Code: header('Content-type: image/png;'); header('Content-length: $iamgesize); So you code will appear something like php Code: $data = mysql_query('SELECT data, filesize FROM images WHERE imageId = 1'); $data = mysql_fetch_assoc($data); header('Content-type: image/png;'); header('Content-length: '.$data['filesize'].''); echo $data['data']; You cannot print out the data with other html content and must load the images through a php file, for example html Code: <div id="user"> <img src="load-image.php?id=23" alt="Image" /> </div> __________________ My Portfolio - Work - Need freelance Work? I've been developing 5 years now, and I learn something new everyday