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sketchMedia · 08-19-2009, 10:02 AM

change the name of the select to Vote101[], this will make PHP process it as an array.

also

PHP Code:


			
foreach (array_keys($_POST) as $key) {
$$key = $_POST[$key];
print "$key is ${$key}<br />";
}

can be done like so:

PHP Code:


			
foreach($_POST as $key => $val)
{
     echo $key .' is: ' . $val  . '<br />';
}

But now you will have arrays in each of the opts so:

PHP Code:


			
    echo 'Vote101 is: <br />';
    foreach($_POST['Vote101'] as $opt)
    {
        echo $opt . '<br />';
    }

should do it.

08-19-2009, 10:02 AM	#2 (permalink)
sketchMedia The Prestige Join Date: Oct 2007 Location: Manchester, UK Posts: 854 Thanks: 32	change the name of the select to Vote101[], this will make PHP process it as an array. also PHP Code: `foreach (array_keys($_POST) as $key) { $$key = $_POST[$key]; print "$key is ${$key}<br />"; }` can be done like so: PHP Code: `foreach($_POST as $key => $val) { echo $key .' is: ' . $val . '<br />'; }` But now you will have arrays in each of the opts so: PHP Code: `echo 'Vote101 is: <br />'; foreach($_POST['Vote101'] as $opt) { echo $opt . '<br />'; }` should do it. __________________ mysql> SELECT * FROM `users` WHERE `users`.`clue` > 0; Empty set (0.00 sec)