View Single Post
Old 08-07-2009, 02:44 PM   #4 (permalink)
russellharrower
The Contributor
 
russellharrower's Avatar
 
Join Date: Jul 2009
Posts: 80
Thanks: 13
russellharrower is on a distinguished road
Default

Fixed the error, however need some help

Code:
<?php

  
		while($row = mysql_fetch_array($result))
		{
		$sitename = $row['sitename'];
		$title = $row['title'];
		$body = $row['body'];
		}
		
		$position=300; // Define how many character you want to display.

	$post = substr($body,$position,1); // Find what is the last character displaying. We find it by getting only last one character from your display message.

	if($post !=" "){ // In this step, if last character is not " "(space) do this step .

	// Find until we found that last character is " "(space) 
	// by $position+1 (14+1=15, 15+1=16 until we found " "(space) that mean character 20) 
	while($post !=" "){
	$i=1;
	$position=$position+$i;

	$post = substr($body,$position,1); 
	}

	}

	$post = substr($body,0,$position); // Display your message
	
	print $sitename;
	echo "<br/>";
	echo $post;
	echo "...";
	echo "<br/><br/>";
	
	
	?>
Now my issue is this part of the code needs to be duplicated

Code:
	print $sitename;
	echo "<br/>";
	echo $post;
	echo "...";
	echo "<br/><br/>";
Is there any way to do this?

Thanks
russellharrower is offline  
Reply With Quote