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wGEric · 07-27-2009, 08:13 PM

Neither of those are passing a variable by reference.

In snippet 1, $p1 is being copied into $a1->accountOwner. Both variables have their own location within the memory. Put an & in front of the variable and both variables will be using the same location in memory making $a1->accountOwner and $p1 essentially the same whereas before they were two different objects in memory.

PHP Code:


			
$p1->name = 'John';
$a1->accountOwner = &$p1;

$a1->accountOwner->name = 'Bob';
echo $p1->name; // returns 'Bob'

07-27-2009, 08:13 PM	#2 (permalink)
wGEric The Acquainted Join Date: Nov 2007 Posts: 166 Thanks: 0	Neither of those are passing a variable by reference. In snippet 1, `$p1` is being copied into `$a1->accountOwner`. Both variables have their own location within the memory. Put an & in front of the variable and both variables will be using the same location in memory making `$a1->accountOwner` and `$p1` essentially the same whereas before they were two different objects in memory. PHP Code: `$p1->name = 'John'; $a1->accountOwner = &$p1; $a1->accountOwner->name = 'Bob'; echo $p1->name; // returns 'Bob'` __________________ Eric