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sketchMedia · 06-08-2009, 02:55 PM

That is because you have not instantiated the object, therefore $this will never contain the reference to the calling object (as it doesn't exist) instead you are using a static call to a class method (which in your case isn't declared static which is bad practice).

You would need something like this:

PHP Code:


			
$tblWriter = new OnlineNowTable(); //create a new object
$tblWriter->writeTable($_SESSION['name']); //run the writeTable method

But looking at your code, I think you need it like this:

PHP Code:


			
$tblWriter = new OnlineNowTable($_SESSION['name']); //create a new object
$tblWriter->writeTable(); //run the writeTable method

06-08-2009, 02:55 PM	#9 (permalink)
sketchMedia The Prestige Join Date: Oct 2007 Location: Manchester, UK Posts: 854 Thanks: 32	That is because you have not instantiated the object, therefore $this will never contain the reference to the calling object (as it doesn't exist) instead you are using a static call to a class method (which in your case isn't declared static which is bad practice). You would need something like this: PHP Code: `$tblWriter = new OnlineNowTable(); //create a new object $tblWriter->writeTable($_SESSION['name']); //run the writeTable method` But looking at your code, I think you need it like this: PHP Code: `$tblWriter = new OnlineNowTable($_SESSION['name']); //create a new object $tblWriter->writeTable(); //run the writeTable method` __________________ mysql> SELECT * FROM `users` WHERE `users`.`clue` > 0; Empty set (0.00 sec)