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allworknoplay · 05-07-2009, 12:29 AM

Ok, I read it and I believe I do get it, but it seems to explain one scenario.

PHP Code:


			
$szVar1 = 'TalkPHP.com';

$szVar2 = 'WiredFlame.com';



$szVar1 =& $szVar2;

Output:

szVar1 is: WiredFlame.com
szVar2 is: WiredFlame.com

But according to what WH said, if you change $szVar1 after the fact, like this:

PHP Code:


			
$szVar1 = 'TalkPHP.com';

$szVar2 = 'WiredFlame.com';



$szVar1 =& $szVar2;  

$szVar1 = 'TalkPHP.com';

You get this:

szVar1 is: TalkPHP.com
szVar2 is: TalkPHP.com

So I can see how if Var1 is referencing Var2, and you change Var2, and you print Var1, it will reveal the new value that was set on Var2...

I just don't understand why in the second code, how is it possible for Var1 to reference through Var2, then you change Var1 in the last line, and then Var2 changes!!!

05-07-2009, 12:29 AM	#12 (permalink)
allworknoplay The Gregarious Join Date: Feb 2009 Location: New York Posts: 645 Thanks: 64	Ok, I read it and I believe I do get it, but it seems to explain one scenario. PHP Code: `$szVar1 = 'TalkPHP.com'; $szVar2 = 'WiredFlame.com'; $szVar1 =& $szVar2;` Output: szVar1 is: WiredFlame.com szVar2 is: WiredFlame.com But according to what WH said, if you change $szVar1 after the fact, like this: PHP Code: `$szVar1 = 'TalkPHP.com'; $szVar2 = 'WiredFlame.com'; $szVar1 =& $szVar2; $szVar1 = 'TalkPHP.com';` You get this: szVar1 is: TalkPHP.com szVar2 is: TalkPHP.com So I can see how if Var1 is referencing Var2, and you change Var2, and you print Var1, it will reveal the new value that was set on Var2... I just don't understand why in the second code, how is it possible for Var1 to reference through Var2, then you change Var1 in the last line, and then Var2 changes!!!