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allworknoplay · 04-23-2009, 02:46 PM

JS closures is still a little bit beyond my understanding but in this article I am reading, I just don't see what the author is pointing out...

He says:

Quote:

Even defining the simplest of functions can create closures:

Code:

var x = 5;
var n = function(){
    y=10;
    return y;
}

Quote:

It doesn't seem like we are creating a closure here, but we are. Why? When we create our function it gets a reference to all variables in its current scope, so we are creating a new reference to our x variable.

Now I keep staring at that code, and I don't see what he's talking about? The function has only one variable in it's scope, and that's the Y variable in which he returns it.

How does that have any affect at all on the X variable?

I am reading it from here:

http://www.htmlgoodies.com/primers/j...le.php/3606701