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Wildhoney · 04-14-2009, 04:44 PM

The following or die will help you to ascertain what the problem is specifically. Run this code and please tell us what the problem is according to MySQL, if you can't figure it out.

php Code:

$query1 = mysql_query("INSERT INTO `prashant_inspirations`.`user_acc` (`uid` ,`username` ,`password`) VALUES(NULL , `$username`,`$password`)") or die (mysql_error());

04-14-2009, 04:44 PM	#2 (permalink)
Wildhoney La Vida es Sueño Join Date: Sep 2007 Location: Oldham Posts: 2,280 Thanks: 90	The following `or die` will help you to ascertain what the problem is specifically. Run this code and please tell us what the problem is according to MySQL, if you can't figure it out. php Code: $query1 = mysql_query("INSERT INTO `prashant_inspirations`.`user_acc` (`uid` ,`username` ,`password`) VALUES(NULL , `$username`,`$password`)") or die (mysql_error()); __________________ The man who comes back through the Door in the Wall will never be quite the same as the man who went out.