TalkPHP - View Single Post - Adding database name within the initial parameters

Salathe · 02-12-2009, 05:05 PM

The error is very clear, an Exception has been thrown but you have nothing in place to catch it. Wrap your code (not the class) in a try/catch block and see which exception is being thrown:

PHP Code:


			
try

{

    $connection = new mysql('localhost', 'root', '', 'cms');

    $query = "SELECT ID, Username, Password, Email FROM admins";

    $connection->query($query);  

}

catch(Exception $e)

{

   echo $e->getMessage();

}

Since you were throwing exceptions, I figured you already knew how to catch them.

02-12-2009, 05:05 PM	#4 (permalink)
Salathe Moderateur Join Date: Apr 2007 Posts: 1,393 Thanks: 5	The error is very clear, an Exception has been thrown but you have nothing in place to catch it. Wrap your code (not the class) in a try/catch block and see which exception is being thrown: PHP Code: `try { $connection = new mysql('localhost', 'root', '', 'cms'); $query = "SELECT ID, Username, Password, Email FROM admins"; $connection->query($query); } catch(Exception $e) { echo $e->getMessage(); }` Since you were throwing exceptions, I figured you already knew how to catch them.