10-20-2008, 11:03 PM
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#10 (permalink)
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Super Moderator
Join Date: Sep 2007
Location: Near you.
Posts: 791
Thanks: 241
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why do i get error on this ?
PHP Code:
$sql = printf(" INSERT INTO
`users`
SET
`username` = '%s',
`password` = '%s',
`email` = '%s',
`rank` = 'normal',
`referral` = '%s',
`joined` = NOW()",
mysql_real_escape_string($username),
mysql_real_escape_string($password),
mysql_real_escape_string($email),
mysql_real_escape_string($referral));
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