TalkPHP - View Single Post - how to capture and show error in oop php to user?

kokjj87 · 10-01-2008, 12:44 PM

hi, i am new to oop php programming style.. i am trying to write a image class to process images, but how do i capture the error(for example when you upload a non image file) and show it to the user?

PHP Code:


			
my image class

----------------------------------------------------

<?php

class image

{

private $allowextension = array("image/gif","image/jpeg","image/png");

private $source;



        function __construct($source)

        {

        $this->source = unserialize($source);



                //check whether the upload file is the extension that is allow

                if(!in_array(($this->source['type']), $this->allowextension))

                {

                  #how do i show an error to the user?.. in a presentable way

                return false;

                }

        }

}



?>

PHP Code:


			
my form

---------------------------------------------------

<?php

include("imageClass.php");





if(isset($_FILES["file"]) && !empty($_FILES["file"]))

{

$upload = serialize($_FILES["file"]);

$image = new image("$upload");

}



else

{?>

<form method="post" enctype="multipart/form-data" action="<?php echo

$_SERVER['PHP_SELF']; ?>" >

<input type="file" name="file" /><input type="submit" value="Upload"/>

</form>



<?php } ?>

I am looking at try and catch but couldn't understand how to show it to the user in a more customizable way(can be use with css).
Thanks in advance!

10-01-2008, 12:44 PM	#1 (permalink)
kokjj87 The Wanderer Join Date: Oct 2008 Posts: 18 Thanks: 0	how to capture and show error in oop php to user? hi, i am new to oop php programming style.. i am trying to write a image class to process images, but how do i capture the error(for example when you upload a non image file) and show it to the user? PHP Code: my image class ---------------------------------------------------- <?php class image { private $allowextension = array("image/gif","image/jpeg","image/png"); private $source; function __construct($source) { $this->source = unserialize($source); //check whether the upload file is the extension that is allow if(!in_array(($this->source['type']), $this->allowextension)) { #how do i show an error to the user?.. in a presentable way return false; } } } ?> PHP Code: `my form --------------------------------------------------- <?php include("imageClass.php"); if(isset($_FILES["file"]) && !empty($_FILES["file"])) { $upload = serialize($_FILES["file"]); $image = new image("$upload"); } else {?> <form method="post" enctype="multipart/form-data" action="<?php echo $_SERVER['PHP_SELF']; ?>" > <input type="file" name="file" /><input type="submit" value="Upload"/> </form> <?php } ?>` I am looking at try and catch but couldn't understand how to show it to the user in a more customizable way(can be use with css). Thanks in advance! Last edited by kokjj87 : 10-01-2008 at 01:58 PM.