07-01-2008, 12:09 AM
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#19 (permalink)
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Super Moderator
Join Date: Sep 2007
Location: Near you.
Posts: 791
Thanks: 241
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if you are trying to give out pointers with a code please don't
give a snippet of code with a new error ;)
PS thank you!
PHP Code:
if(!$result) {
if (defined('DEBUG')) {
Quote:
ps, who said i wont fix it up later on?..the code..
think of how much time you save if you just code what comes to mind, and not worry about the damn css..
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