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delayedinsanity · 06-16-2008, 12:09 AM

Technically you could have an unlimited amount of optional arguments. The first way, and probably the least aesthetically pleasing would be to define a single argument and check if it's an array or not;

PHP Code:


			
function snuffleluffagus ($mArgs) {

    if (is_array($mArgs)) {
        $intNumArgs = count($mArgs);
        // ..
    } else {
        // ..
    }

}

..and the second would use PHP's built in functionality, with func_num_args() and func_get_args().

PHP Code:


			
// example borrowed directly from PHP.net

function foo () {

    $numargs = func_num_args();
    echo "Number of arguments: $numargs<br />\n";
    if ($numargs >= 2) {
        echo "Second argument is: " . func_get_arg(1) . "<br />\n";
    }
    $arg_list = func_get_args();
    for ($i = 0; $i < $numargs; $i++) {
        echo "Argument $i is: " . $arg_list[$i] . "<br />\n";
    }

}

-m

06-16-2008, 12:09 AM	#7 (permalink)
delayedinsanity The Gregarious Join Date: Mar 2008 Location: Cana'derr Posts: 653 Thanks: 24	Technically you could have an unlimited amount of optional arguments. The first way, and probably the least aesthetically pleasing would be to define a single argument and check if it's an array or not; PHP Code: `function snuffleluffagus ($mArgs) { if (is_array($mArgs)) { $intNumArgs = count($mArgs); // .. } else { // .. } }` ..and the second would use PHP's built in functionality, with func_num_args() and func_get_args(). PHP Code: `// example borrowed directly from PHP.net function foo () { $numargs = func_num_args(); echo "Number of arguments: $numargs<br />\n"; if ($numargs >= 2) { echo "Second argument is: " . func_get_arg(1) . "<br />\n"; } $arg_list = func_get_args(); for ($i = 0; $i < $numargs; $i++) { echo "Argument $i is: " . $arg_list[$i] . "<br />\n"; } }` -m