05-29-2008, 02:43 PM
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#15 (permalink)
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The Frequenter
Join Date: Oct 2007
Location: Manchester, UK
Posts: 469
Thanks: 26
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I think this should do it, there is probably a better way of doing it but it works for me:
PHP Code:
$date = '30-03-2008';
$date2 = '31-03-2008';
//get the offset
$dateTime1 = new DateTime($date);
$dateTime2 = new DateTime($date2);
$dstZone = new DateTimeZone('Europe/London');//change accordingly
echo 'Difference: ',((strtotime($date2) + $dstZone->getOffset($dateTime2)) - (strtotime($date) + $dstZone->getOffset($dateTime1))) / 86400, ' Days';
outputs: 1 day.
edit: i think this is for php 5.2.x not sure about 5.1.x as i dunno when these classes were added, any1 know?
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