02-14-2008, 01:11 AM
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#7 (permalink)
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The Prestige
Join Date: Dec 2007
Posts: 1,044
Thanks: 193
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Quote:
Originally Posted by Alan @ CIT
What does $type actually contain after you have uploaded a file? Your substr() starts checking at character 6, and returns 12 characters which I'm guessing won't match much.
If $type just contains the file extension (without the .), then substr($type) would do it. If it contains the full filename, then you could use substr($type, -3) to get the last 3 characters of the filename (likely the extension).
Alternativly, use the pathinfo() function on the filename to get the extension:
PHP Code:
$file = '/home/www/images/myimage.jpeg';
$fileParts = pathinfo($file);
echo $fileParts['extension'];
// echo's: jpeg
Alan |
You're a life saver. :D Sorry but the people who NEED it are getting pissed off. :P
Also, its $_FILES['file']['type'], I then take out image/ and use the others.
Update: Now it says invalid image for me >.<
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VillageIdiot can have my babbies ;d
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